Thursday 13th September 2012 Section 3
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September 13, 2012, 8:24 am
Filed under: Uncategorized
Filed under: Uncategorized
Sampling techniques and Species richness vs Species eveness
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Nisitha and Yuan table:
Quadrat A B C D E
1 80% 20%
A= Grass
Comment by nisithadissanayake September 13, 2012 @ 6:48 pmB= Clover
Hannah and Spencer
Quadrat A B C D E
1 80% 84% 52% 100% –
A = Grass
Comment by hannahgooch September 13, 2012 @ 7:39 pmB = Dandelion
C = Ladies Bedstraw
D = Clover
Measuring biodiversity
Species richness – This is the number of different species found in a certain area; the more species found, the higher the richness e.g 2 different species found means a species richness of 2. However, species richness does not tell us which species are common or rare.
Species evenness – This is the number of each type of species, recorded as either a percentage or as a raw number. There are two possible outcomes; either lots of species with 1 or 2 dominant kinds, or lots of species of equal number. To differentiate organisms, use a species key to decided whether or not they are the part of the same species.
If it is impractical to count individually how many of each species there are, use the ACFOR scale (abundant, common, frequent, occasional, rare) as a rough indicator.
Areas with many different species tend to be more stable and are better at coping with environmental change. If an area only contains one type of species, then a change of conditions such as temperature could result in the entire area dying.
Results for Phil and Candice:
Quadrat 1: Species A 85%; Species B 7%; Species C 13%
Quadrat 2: Species A 80%; Species B 20%;
A = Grass
Comment by phillipmarriage September 13, 2012 @ 10:26 pmB = Clover
C = Dandelion
This is actually really good detail and all
Comment by halima95 September 16, 2012 @ 8:59 amCan add to my notes now
Measuring biodiversity
Species richness – This is the number of different species found in a certain area; the more species found, the higher the richness e.g 2 different species found means a species richness of 2. However, species richness does not tell us which species are common or rare.
Species evenness – This is the number of each type of species, recorded as either a percentage or as a raw number. There are two possible outcomes; either lots of species with 1 or 2 dominant kinds, or lots of species of equal number. To differentiate organisms, use a species key to decided whether or not they are the part of the same species.
If it is impractical to count individually how many of each species there are, use the ACFOR scale (abundant, common, frequent, occasional, rare) as a rough indicator.
Areas with many different species tend to be more stable and are better at coping with environmental change. If an area only contains one type of species, then a change of conditions such as temperature could result in the entire area dying.
Results for Phil and Candice:
Quadrat 1: Species A 85%; Species B 7%; Species C 13%
Quadrat 2: Species A 80%; Species B 20%;
A = Grass
Comment by phillipmarriage September 13, 2012 @ 10:43 pmB = Clover
C = Dandelion
Quadrat 1: Species A – 75% Species B – 20% Species C – 5%
A= Grass
B= Clover
C= Dandelion
Jake and gautam
Comment by jakepalmer1 September 14, 2012 @ 3:28 pmhttp://e360.yale.edu/feature/finding_new_species_the_golden_age_of_discovery/2129/
Comment by yuansun September 14, 2012 @ 6:09 pmBen and Jaimie
A= grass (61%)
Comment by bensubhani September 14, 2012 @ 8:19 pmB= clover (11%)
C=Dandilion (4%)
D=lady’s bedstraw (22%)
E= Other plant (unidentified) (2%)
Halima and Mehleen table
Comment by halima95 September 16, 2012 @ 8:45 amQuadrat 1
Species A (grass) -100%
Species B (flower) – 88%
Species C (Dandelion leaves/flower) – 12%
Species D (3-leaf clovers) – 88%
Ignore the above table and Mehleen’s one. They’re wrong. This is the actual rresult. The key is still the same though.
Comment by halima95 September 17, 2012 @ 8:18 amA – 62%
B – 28%
C – 8%
D – 2%
Mehleen and Halima
A (grass) = 100%
Comment by mehleen September 16, 2012 @ 8:51 amB (Lady’s Bedstraw) = 16%
C (Dandelion) = 12%
D (Clovers) = 88%
Deelan and Alex
A=Grass Q1: 65% Q2: 80% Q3: 70%
Comment by deelanvadher September 16, 2012 @ 11:37 amB=Clover Q1: 20% Q2: 20% Q3: 15%
C=Dandelion Q1: 10% Q2: — Q3: 5%
D=Ladies’ Bedstraw Q1: 5% Q2: — Q3: 10%
http://www.sciencedaily.com/news/plants_animals/new_species/
Comment by deelanvadher September 16, 2012 @ 11:43 amDan and Matt: Coordinates (10,2)
A= Grass (90%)
Comment by danialnaqvi September 16, 2012 @ 3:05 pmB= Clovers (7%)
C= Dandelions (3%)
Helen and Hanali
Comment by helenquah September 17, 2012 @ 10:20 amA – 100% – grass
B – 25% – dandelion
C – 100% – Ladies bed straw
http://www.bbc.co.uk/nature/13630240
Comment by gautammenon1 September 17, 2012 @ 8:25 pmi’m beasting
Comment by gautammenon1 September 17, 2012 @ 8:27 pmhttp://www.bbc.co.uk/news/science-environment-11607299
http://www.trust.org/alertnet/news/protecting-biodiversity-key-to-food-security-adaptation-expert
Comment by jakepalmer1 September 18, 2012 @ 5:40 pmshort article on the importance of biodiversity